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Subject:	Re: Hole break out
From:	Guy Ramsey <[log in to unmask]>
Reply To:	TechNet E-Mail Forum.
Date:	Tue, 16 Sep 2003 13:52:41 -0400
Content-Type:	multipart/alternative
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IPC-A-600F and IPC-6012A have the same requirements for these features.
Table 3-5 of the 6012A may be less verbose But it says the same thing.
For Class 3, when the drilled through hole is plated (supported) an
external ring shall not be less than 0.002". Measured from the inside of
the hole to the outside of the remaining ring. If the drilled hole is
not plated (unsupported) then an external ring shall not be less than
0.0059". In any event some further reduction, not more than  20% due to
pits, dents, nicks and the like, is acceptable.

The internal rings have different requirements. They are described in
Clause 3.4.2 in the 6012A and Clause 3.3.1 of the IPC-A-600F. For Class
3, one mil min. measured as shown in Figure 3-1.

-----Original Message-----
From: TechNet [mailto:[log in to unmask]] On Behalf Of Victor Hernandez
Sent: Tuesday, September 16, 2003 1:15 PM
To: [log in to unmask]
Subject: [TN] Hole break out



Fellow TechNetters,

    The QUESTION is for clarification on HOLE BREAKOUT;
   IPC-A-660F sec. 2.10.1.2  -  2.10.4 refers to Annular rings
Supported and Unsupported.

     What is the DIFFERENCE between the two categories.   Does this
apply to internal annular for hole breakout?

   Is there another guideline which is more straight forward?


Victor,


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