Yes, I agree with the fact that the Aircraft Might have Hit the Ground with the force of 700G's, Killing everyone. My Point is that Mr. Patel worded his email " The Aircraft can take on 700G Force" To me this sounds like he is saying the aircraft is structurally sound to with stand a force of 700G's.
My Perception only!!
-----Original Message-----
From: Tim Weller [SMTP:[log in to unmask]]
Sent: Thursday, October 11, 2001 10:46 AM
To: [log in to unmask]
Subject: Re: [TN] Question for the physics "gurus"
It's not the in-flight stresses, it's the sudden impact with the ground.
"Sarrouf, Michael" wrote:
Ken,
Coming from a Pilot's stand point. There is no way an aircraft could pull 700g's. 7G's yes. People black out at 4.5-5g's if they are not wearing a Gsuit like the military pilots wear. Military pilots can pull up to 9g's but they are wearing the Gsuit. Most commercial aircraft might have the structural strength to with stand a 16G load Factor. At 700G's a person weighing 150lbs would weigh 35,000lbs.
Are you sure it was not 7G's the aircraft was pulling??
Mike
-----Original Message-----
From: Ken Patel [SMTP:[log in to unmask]]
Sent: Wednesday, October 10, 2001 6:29 PM
To: [log in to unmask]
Subject: Re: [TN] Question for the physics "gurus"
All,
If G force is the gravitation force acting on the object then why many times an object is
being designed to take so may G forces. What I have heard that voice recorder of the plane
that went down in Pennsylvania can take on 700G force! So, if the free fall is 1 G then why
design 700 times safer. So, height above the ground does matter. May be I got to take a look
at the physic's book unless someone explain in layman's term.
re,
Ken Patel
Timothy Reeves wrote:
> No Jason,
> I am not a guru, but that's OK. They are not interconvertible. One is a
> measure of force, the other acceleration (actually a dimensionless
> multiplier of the standard gravitational acceleration, g, 9.8 m/s^2). If you
> have an object in mind of a known mass, you could find the force exerted on
> it given the acceleration ("G's") by F = m a.
>
> Example: 100 gram object subjected to 5 G's ---------> F = 0.1 kg * 5 * 9.8
> m/s^2 = 4.9 Newtons or 0.5 kilogram force or 1.1 lb-force.
>
> Tim Reeves
>
> -----Original Message-----
> From: Jason Gregory [ <mailto:[log in to unmask]>]
> Sent: Tuesday, October 09, 2001 9:01 AM
> Subject: Question for the physics "gurus"
>
> How do you convert pound/kilogram to G-force? Is this convertable? Since
> G-force is somewhat time derived and pound/kilogram is force derived?
> Any help is appreciated.
>
> Jason Gregory
> Software Specialist - NPI Group
> SCI Systems/Plant 2
> 13000 S. Memorial Pkwy.
> Huntsville, AL. 35803
> (256) 882-4107 x3728
> [log in to unmask]
>
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