Now your starting to get into the theories of two masses vastly different to one another developing a form of gravity between them. The same thing applies to one very large mass exterting a form of gravity on a very small mass, i.e. person and a planet. Or for example, a marble being dropped from the top of a skyscraper. As the marble drops from the top, because the skyscraper is regarded as infinitely large in comparison to the marble, the Skyscraper forms a source of gravity on the marble, and attracts the marble towards the building. This is why if you spit from the top of the Empire State Building, your spit will never reach the ground, but end up being pulled onto the outside wall of the building. Fascinating eh? -----Original Message----- From: Bissonnette, Jean-Francois [mailto:[log in to unmask]] Sent: Wednesday, 10 October 2001 09:19 To: [log in to unmask] Subject: Re: [TN] Question for the physics "gurus" Just a little note here. Pounds and Kilograms cannot be put in the same basket as the weight is function of the mass. For example, your mass on earth or on the moon or on Jupiter (supposing it was a solid planet) is always the same. However your weight will change (approx 1/6 on the moon). If I'm not wrong, you'll find your weight using the formula: k*m1*m2/d^2 where k is a constant m1 is earth mass in kilograms m2 your mass in kilograms d is the distance between earth center of gravity and you. So Kilograms and pounds are not the same. my two cents... -----Original Message----- From: Michael Bell [mailto:[log in to unmask]] Sent: Tuesday, October 09, 2001 3:54 PM To: [log in to unmask] Subject: Re: [TN] Question for the physics "gurus" Brian, Wrong, you can compare the weight and force. This comes back to the common equation of F=MA. Force = Mass x Acceleration. Here you use the simple gravity acceleration to compare a weight factor to the force it applies. i.e. A persons weight can be discribed as a force due to the gravity acceleration constant 9.8m/s. Force a persons weight applies on the ground is F=70Kg x 9.8m/s. So therefore, you can describe a weight as a force, provided this is reviewed in the correct axis. If we were talking in a horizontal axis, this theory doens't apply. Perhaps, you were refering to the Pounds/Kilogram reference earlier. I think Jason just used that (Pounds/Kilograms) as a reference to weight regardless of your units and not to the actual ratio itself. Cheers -----Original Message----- From: Brian Ellis [mailto:[log in to unmask]] Sent: Wednesday, 10 October 2001 08:42 To: [log in to unmask] Subject: Re: [TN] Question for the physics "gurus" Jason, Pound/kilogram is a ratio of 1:2.2046 or 0.4536 and cannot have anything whatsoever to do with an acceleration which can be expressed only in distance/unit time^2. Aren't you barking up the wrong monkey puzzle? Brian Jason Gregory wrote: > > How do you convert pound/kilogram to G-force? Is this convertable? Since G-force is somewhat time derived and pound/kilogram is force derived? > Any help is appreciated. > > Jason Gregory > Software Specialist - NPI Group > SCI Systems/Plant 2 > 13000 S. Memorial Pkwy. > Huntsville, AL. 35803 > (256) 882-4107 x3728 > [log in to unmask] > > ---------------------------------------------------------------------------- ----- > Technet Mail List provided as a free service by IPC using LISTSERV 1.8d > To unsubscribe, send a message to [log in to unmask] with following text in > the BODY (NOT the subject field): SIGNOFF Technet > To temporarily halt delivery of Technet send the following message: SET Technet NOMAIL > Search previous postings at: www.ipc.org > On-Line Resources & Databases > E-mail Archives > Please visit IPC web site (http://www.ipc.org/html/forum.htm) for additional > information, or contact Keach Sasamori at [log in to unmask] or 847-509-9700 ext.5315 > ---------------------------------------------------------------------------- ----- ---------------------------------------------------------------------------- ----- Technet Mail List provided as a free service by IPC using LISTSERV 1.8d To unsubscribe, send a message to [log in to unmask] with following text in the BODY (NOT the subject field): SIGNOFF Technet To temporarily halt delivery of Technet send the following message: SET Technet NOMAIL Search previous postings at: www.ipc.org > On-Line Resources & Databases > E-mail Archives Please visit IPC web site (http://www.ipc.org/html/forum.htm) for additional information, or contact Keach Sasamori at [log in to unmask] or 847-509-9700 ext.5315 ---------------------------------------------------------------------------- ----- ---------------------------------------------------------------------------- ----- Technet Mail List provided as a free service by IPC using LISTSERV 1.8d To unsubscribe, send a message to [log in to unmask] with following text in the BODY (NOT the subject field): SIGNOFF Technet To temporarily halt delivery of Technet send the following message: SET Technet NOMAIL Search previous postings at: www.ipc.org > On-Line Resources & Databases > E-mail Archives Please visit IPC web site (http://www.ipc.org/html/forum.htm) for additional information, or contact Keach Sasamori at [log in to unmask] or 847-509-9700 ext.5315 ---------------------------------------------------------------------------- ----- WABTEC CORPORATION CONFIDENTIALITY NOTE The content contained in this e-mail transmission is legally privileged and confidential information intended only for the use of the individual or entity named herein. 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