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December 1997

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Subject:
Re: area of a cylinder
From:
Fred Paul <[log in to unmask]>
Reply To:
[log in to unmask]
Date:
Wed, 17 Dec 1997 13:26:53 -0800
Content-Type:
TEXT/PLAIN
Parts/Attachments:
TEXT/PLAIN (58 lines) 
Ed,
       The formulas I wrote were for the special case of a
'right' cylinder,  where the two circular ends are parallel to
one another and perpendicular to the center line between
their centers (picture an unopened, undeformed tin can).
There are handbooks that can provide other special case
formulae for irregular cylinders.  If you don't have a 'right'
cylinder, describe what type of cylinder from which you want
the area or volume.


-- Fred Paul

On Wed, 17 Dec 1997 13:06:06 pst Fred Paul wrote:

> From: Fred Paul <[log in to unmask]>
> Date: Wed, 17 Dec 1997 13:06:06 pst
> Subject: area of a cylinder
> To: TechNet <[log in to unmask]>
>
> Ed,
>
>         The area of a cylinder is the circumference multiplied
> by the height.  (e.g. 2*pi*r*h).  Where r = radius (in ft), pi
is
> approx. 3.1416, and h is the height of the cylinder (in ft).
> The result will be the area in square feet.  If you want the
> volume of the cylinder, multiply the area of the circular end
> by the height (i.e. pi*rE2*h), where pi is again 3.1416, r =
> the radius of the cylinder, and h = the height of the
cylinder.
> All these units must be in ft to yeild cubic feet.  rE2
stands
> for the radius of the cylinder, squared.
>
> Fred J. Paul, Staff Engineer
> PCB Operations, FLUKE CORPORATION
> direct:  425 356 5734  fax:  425 356 6070
> [log in to unmask]
> VISIT THE FLUKE WEB SITE WWW.FLUKE.COM
>
Fred J. Paul, Staff Engineer
PCB Operations, FLUKE CORPORATION
direct:  425 356 5734  fax:  425 356 6070
[log in to unmask]

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