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November 1997

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Subject:
From:
Jeff Seeger <[log in to unmask]>
Reply To:
TechNet Mail Forum.
Date:
Tue, 4 Nov 1997 13:59:39 -0500
Content-Type:
text/plain
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text/plain (73 lines)
Max Harris wrote:
>
>      Jeff,
>
>      I agree with everything you have said, but my original question still
>      stands. How do I connect to a node that is being guarded on every
>      layer of the PCB without breaking the ring on at least one layer, or
>      routing from standoffs, on an external layer, over the top of the
>      ring?
>
        Max,

        Sorry if I wasn't clear enough.  The guard ring and/or other
        isolation techniques must include the rest of the path leading
        up to the op-amp, all the way back to where it becomes high-
        impedance.  It had best be very short.

> Author:  Jeff Seeger <jseeger*remove_to_reply*@appliedcad.com> at smtp_gway
> Date:    11/3/97 4:27 PM
>
> Max Harris wrote:
> >
> >      Can anyone out there help me with the subject of using guard rings
> >      around op amp inputs to minimize leakage at the high impedance nodes?
> >      I will be using an FR-4 PCB, multilayer, PTH technology. From what
> >      I've read, it is suggested that the guard rings be placed on every
> >      layer.
>
>         The nature of your question implies an analog world, where high
>         impedance can mean in the meg-ohms - not the impedance range of the
>         board itself.  With an input _that_ sensitive, it is advisable to
>         make full use of the fact that Farraday was right.
>
>         For the guard ring to be fully functional, you want sheilding be-
>         tween your input and _any_ other possible affector.  This may in-
>         clude putting a void in any plane layers, and if the op-amp is a
>         through-hole part you should carry the guard to all layers.
>
> >      This begs the question: "How do I then connect traces to the
> >      node being guarded?". Also, any traces that do connect to the guarded
> >      node and then run outside of the ring are now subject to the same
> >      leakage that the original node was.
> >
>         In such an impedance range, the source of your signal had better
>         be close enough to not be an issue as far as including it in your
>         guard ring.  If there is a large value resistor in the circuit as
>         it leads up to your input, this is the point where the impedance
>         jumps, and is the point where the guard should extend to.  If not,
>         then it may be such a signal back to the last device, connector,
>         or summing junction.
>
>         Length in such a signal path is your enemy.
>
>         Good luck,

--

      Jeff Seeger                             Applied CAD Knowledge Inc
      Chief Technical Officer                      Tyngsboro, MA  01879
      jseeger "at" appliedcad "dot" com                    978 649 9800

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