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| Date: | Thu, 29 Sep 2005 15:31:07 -0500 |
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A baseball question:
Who's on first?
>From: Chris Ball <[log in to unmask]>
>Reply-To: TechNet E-Mail Forum <[log in to unmask]>, [log in to unmask]
>To: [log in to unmask]
>Subject: Re: [TN] Okay, all you real smart guys.........
>Date: Thu, 29 Sep 2005 16:25:46 -0400
>
>Based on that, I was gonna interject something about an anti-gravity ray
>being a weapon of mass destruction, but it wasn't making any sense at all.
>Then I realized.....
>
>The mass of an object is not dependent on gravity and therefore is
>different from but proportional to its weight.
>
>(sigh)
>
>Ask me a baseball question.
>
>-Chris
>
>
>
>
>
>
> "Morse, Carrie"
> <[log in to unmask]> To:
>[log in to unmask]
> Sent by: TechNet cc:
> <[log in to unmask]> Subject: Re:
>[TN] Okay, all you real
> smart
>guys.........
> 09/29/2005 04:04 PM
> Please respond to TechNet
> E-Mail Forum; Please
> respond to "Morse, Carrie"
>
>
>
>
>
>
>
>Mass is the Weight of the object divided by Gravity: M=w/g
>
>I would weight the object and divide by g
>
>-Carrie
>
>
>
>-----Original Message-----
>From: TechNet [mailto:[log in to unmask]] On Behalf Of Jason Gregory
>Sent: Thursday, September 29, 2005 3:42 PM
>To: [log in to unmask]
>Subject: [TN] Okay, all you real smart guys.........
>
>Can someone point me in the right direction on determining mass of
>components of a PCB, knowing:
>
>the weight of a bare PCB
>the weight of a populated PCB
>number of terminations
>etc.
>
>Who knows the formula?
>
>TIA
>
>Jason Gregory
>Manufacturing Engineer
>Innova Electronics
>(281)653-5593
>(281)653-5594 fax
>(281)212-0844 cell
>[log in to unmask]
>
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De todo para la Mujer Latina http://latino.msn.com/mujer/
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