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June 2004

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Subject:
From:
Roger Stoops <[log in to unmask]>
Reply To:
TechNet E-Mail Forum.
Date:
Fri, 11 Jun 2004 11:35:31 -0400
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Add to that the fact that operating voltages have decreased from 5V to under 2V, so it takes less time for a signal to change states.

Roger M. Stoops, CID+
Trimble Navigation Ltd., Dayton, OH, USA
Ph: +01 937.245.5288
Fax: +01 937.233.7511


-----Original Message-----
From: TechNet [mailto:[log in to unmask]]On Behalf Of Ahne Oosterhof
Sent: Friday, June 11, 2004 11:29 AM
To: [log in to unmask]
Subject: Re: [TN] Relation between physical size and frequency??


It's the other way around. As the chip gets smaller resulting from smaller
components on the chip that have lower capacitance which requires less
current to get them from one state to another (from '0' to '1' to from 'low'
to 'high') and it does not generate more heat!! and which allows you to do
it faster ---> higher frequency.
That is why chipmakers are racing towards nanometer technology (smaller
transistors and connecting runs) so that ultimately they need only one
electron to get form a zero to a one (except for a host of other problems).

Have a nice weekend.
Ahne.


-----Original Message-----
From: TechNet [mailto:[log in to unmask]]On Behalf Of Saravanan
Sent: Friday, June 11, 2004 5:06
To: [log in to unmask]
Subject: [TN] Relation between physical size and frequency??


Hi,
        Could some one explain me quantitatively why the physical size of an
electronic chip reduce in size as the operating frequency increases. I
remember the P2 processor is conspicuously bigger than the latest P4
processor. What is the reason behind?

Regards,
Saravanan.K

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