It's defined by the area under the normal distribution curve. The easiest
way is to use a set of tables where this is calculated already. So subtract
your 800 ppm from 1 million, 999200, express this as a decimal 0.9992, then
look up the tables to find this and the related sigma value is 3.16. There
is a formula to calculate the area under the normal distribution curve for a
given sigma, but I recommend the tables.
Regards
Edward Brunker
Principal Process Engineer
-----Original Message-----
From: Collins, Graham [mailto:[log in to unmask]]
Sent: Tuesday, February 08, 2000 5:46 PM
To: [log in to unmask]
Subject: Re: [TN] Subj: Six Sigma
Is there a formula one can use to come up with these numbers? E.G. if my
process yield last month was 800 PPM, can I crunch that number and say we
were at 4.8 sigma?
- Graham Collins
-----Original Message-----
From: Hollandsworth, Ron [mailto:[log in to unmask]]
Sent: Tuesday, February 08, 2000 11:29 AM
To: [log in to unmask]
Subject: Re: [TN] Subj: Six Sigma
Dave:
Thanks this is what I was looking for. I will chart this out and pass it on
to the Mfg. Engineer who ask the question.
Thanks to all the replys. (Terri, Lou, & Ed)
Appreciate the quick response.
Ron Hollandsworth
-----Original Message-----
From: David Fish [mailto:[log in to unmask]]
Sent: Tuesday, February 08, 2000 1:09 PM
To: Hollandsworth, Ron
Subject: Re: [TN] Subj: Six Sigma
Ron: From Breyfogle (ISBN 0471296597):
Spec limit|Defective ppm - no mean shift|Defective ppm - 1.5 sigma mean
shift
±1 sigma|317300|697700
±2 sigma|45500|308700
±3 sigma|2700|66810
±4 sigma|63|6210
±5 sigma|0.57|233
±6 sigma|0.002|3.4
Dave Fish
"Hollandsworth, Ron" wrote:
> Good Morning TechNetters!
> Here is a brain teaser for this early morning. Thinking six sigma. Six
> sigma is suppose to be 3.4 PPM. Good! Now what is five sigma, four,
three,
> two , one. There is a chart that shows that relationship of a certain
sigma
> and the PPM associated with that particular sigma value.
>
> Ok, the first five to get the right answer will be eligible to go on to
the
> "Who wants to be a Black Belt" show. Enough levity, can someone help me
> out. Do you know the chart I am referring to? Can you send me the values
> and I'll make a chart.
>
> Grasshopper Ron
>
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