Hi technetters !
We are performing tests on black oxide to reduced oxide conversion .
From theoretical point of view , the basic chemical reaction is :
2 CuO +reducer = Cu2O .
It mean , reduced oxide will weight 90% of black oxide :
( 2 * ( 63.5 + 16 )) / ( 2 * 63.5 + 16 )
What are the practical results ?
Edward Szpruch
Eltek Ltd - Israel
Tel 972 3 9395050
Fax 972 3 9309581
E-mail : [log in to unmask]